![Method name is not highlighted when the output type is a reference in C++ · Issue #6546 · codemirror/codemirror5 · GitHub Method name is not highlighted when the output type is a reference in C++ · Issue #6546 · codemirror/codemirror5 · GitHub](https://user-images.githubusercontent.com/31668662/103369431-c72af180-4ad2-11eb-9507-e319bdc7df76.png)
Method name is not highlighted when the output type is a reference in C++ · Issue #6546 · codemirror/codemirror5 · GitHub
![luna 🐀 on Twitter: "can someone explain to me why `typename` is required here? clang screams at me if I omit it (error below) but it's not required for the first function? luna 🐀 on Twitter: "can someone explain to me why `typename` is required here? clang screams at me if I omit it (error below) but it's not required for the first function?](https://pbs.twimg.com/media/EE_OtrtWkAMXYGK.png)
luna 🐀 on Twitter: "can someone explain to me why `typename` is required here? clang screams at me if I omit it (error below) but it's not required for the first function?
![Parameter estimation framework with Ipopt. template phi is a function... | Download Scientific Diagram Parameter estimation framework with Ipopt. template phi is a function... | Download Scientific Diagram](https://www.researchgate.net/publication/277604491/figure/fig3/AS:642915869143042@1530294496873/Parameter-estimation-framework-with-Ipopt-template-typename-T-phi-is-a-function.png)