There are two chords AB and CD in a circle. AB=10cm and CD=8cm, and the radius of the circle is 12cm. What is the distance of each chord from the center of
In the adjoining figure, chord AB ≅ chord CD. Prove that, arc AC = arc BD. - Sarthaks eConnect | Largest Online Education Community
![In a circle, chord AB bisects chord CD at E. If AE equals 8 and BE equals 9 find the length of CD in simplest radical form. | Homework.Study.com In a circle, chord AB bisects chord CD at E. If AE equals 8 and BE equals 9 find the length of CD in simplest radical form. | Homework.Study.com](https://homework.study.com/cimages/multimages/16/chordbisector5950258478866690943.png)
In a circle, chord AB bisects chord CD at E. If AE equals 8 and BE equals 9 find the length of CD in simplest radical form. | Homework.Study.com
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